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One mole of N₂H₄ loses l0 mole of electrons to form a new compound Y. Assuming that all nitrogen appears in the new compound, what is the oxidation number of nitrogen in Y (There is no change in the oxidation state of hydrogen)?

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answer is B.

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Detailed Solution

The oxidation state of N in hydrazine is -2.

1 mole of hydrazine contains 2 moles of N and loses 10 moles of electrons.

Hence, 1 N atom will lose 5 electrons. Hence, its oxidation number will increase by 5.

Hence, the oxidation number of N in compound A will be −2+5=+3.

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