One mole of N₂H₄ loses ten moles of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y?
Note: There is no change in the oxidation state of hydrogen.

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answer is 3.

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Detailed Solution

The oxidation state of N in hydrazine is -2. 1 mole of hydrazine contains 2 moles of N and loses 10 moles of electrons. Hence, 1 N atom will lose 5 electrons. Hence, its oxidation number will increase by 5.

Hence, the oxidation number of N in compound A will be -2+5=3.

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