One mole of N2O4(g) at 300 K is kept in a closed container under one atmospheric pressure. It is heated to 600 K, when N2O4 decomposes to NO2. If the resultant pressure is 2.4 atm. The degree of dissociation of N2O4 is_________%.

N2O4⇄20NO2 (initial moles)At equilibrium moles1−α 2α n1=1n2=1−α+2α=1+α n2=1+α P1V=n1RT1P2V=n2RT2 1.02.4=1×300(1+α)600α=0.2=20%

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

One mole of N₂O₄(g) at 300 K is kept in a closed container under one atmospheric pressure. It is heated to 600 K, when N₂O₄ decomposes to NO₂. If the resultant pressure is 2.4 atm. The degree of dissociation of N₂O₄is_________%.

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is 20.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$N_{2} O_{4} ⇄ \underset{0}{2} {NO}_{2}$ (initial moles)At equilibrium moles
$\begin{array}{llll} 1 - α 2 α n_{1} = 1 n_{2} = 1 - α + 2 α = 1 + α n_{2} = 1 + α \end{array} \frac{P_{1} V = n_{1} {RT}_{1}}{P_{2} V = n_{2} {RT}_{2}} \frac{1 .0}{2 .4} = \frac{1 \times 300}{(1 + α) 600} α = 0 .2 = 20 %$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE