One mole of O₂ gas having a volume equal to 22.4 litres at 0⁰C and 1 atmospheric pressure in compressed isothermally so that its volume reduces to 11.2 litres. The work done in this process is

$\begin{array}{l}{\mathrm{V}}_1=22.4\text{ litres };{\mathrm{V}}_2=11.2\text{ litres }\\ \mathrm{R}=1\text{ atmospheric pressure }\\ \mathrm{T}=273+0=273\mathrm{k};\mathrm{n}=1\text{ mole }\\ \mathrm{W}=2.303\mathrm{nRTlog}\left(\frac{{\mathrm{V}}_2}{{\mathrm{V}}_1}\right)\\ =1\times 8.314\times 273\times 2.3026{\log }_{10}\left(\frac{11.2}{22.4}\right)\\ =273\times 2.3026\times 8.314\times (-0.3010)\\ =8.314\times 2.3026\times 273\times (-0.3010)\\ =-1573.10\approx -1572.5\mathrm{J}\end{array}$