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Q.

One mole of O₂ gas having a volume equal to 22.4 liters at 0°C and 1 atmospheric pressure is compressed isothermally so that its volume reduces to 11.2 liters. The work done in this process is (ln 2=0.693)

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a

1728 J

b

–1728 J

c

–1572.5 J

d

1672.5 J

answer is D.

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Detailed Solution

V₁ = 22.4 litres; V₂ = 11.2 litres

R = 8.314 J/mol - K

T = 273 + 0 = 273 K; n = 1 mole

$W = nRT \ln (\frac{v_{f}}{v_{i}})$

$= 1 \times 8.314 \times 273 \times \ln (\frac{11.2}{22.4})$

= - 8.314 × 273 × 0.693 J

= - 1572.5 J

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One mole of O2 gas having a volume equal to 22.4 liters at 0°C and 1 atmospheric pressure is compressed isothermally so that its volume reduces to 11.2 liters. The work done in this process is (ln 2=0.693)