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Q.

One mole of PCl₅ (g) was heated in a 1L closed flask at 500 K. At equilibrium, 0.1 mole of Cl₂ ( g) was formed. What is its K_p (in atm)?
$(Given R = 0.082 Latm {mol}^{- 1} K^{- 1})$

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a

$2.7 \times 10^{- 4}$

b

$0.0111$

c

$90.0$

d

$0.455$

answer is B.

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One mole of PCl5 (g) was heated in a 1L closed flask at 500 K. At equilibrium, 0.1 mole of Cl2 ( g) was formed. What is its Kp (in atm)?(GivenR=0.082Latmmol−1K−1)