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One mole of $O_{2}$ gas having a volume equal to $22.4$ litres at $0^{0} C$ and 1 atmospheric pressure in compressed isothermally so that its volume reduces to $11.2$ litres. The work done in this process is

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$- 1572.5 J$

$- 1728 J$

$1728 J$

$1672.5 J$

answer is D.

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Detailed Solution

$W = 2.303 n R T \log_{10} (\frac{V_{2}}{V_{1}})$

$= 2.303 \times 8.314 \times 273 \log_{10} (\frac{11.2}{22.4})$

$= - 1572.5 J$

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