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Q.

One mole of $P_{4}$ molecule contains

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a

1 molecule of P

b

4 molecules of P

c

$\frac{1}{4} \times 6.022 \times 10^{23} of P$

d

$24.088 \times 10^{23} atoms of P$

answer is D.

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Detailed Solution

One mole of any substance has Avogadro’s number of particles. So,

One mole of $P_{4}$ molecule has $4 \times 6.022 \times 10^{23} = 24.088 \times 10^{23}$ .

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