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Q.

One of the 15th roots of $- 1$ is

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a

$\cos 0$

b

$c i s \frac{14 π}{15}$

c

$c i s \frac{13 π}{15}$

d

$c i s \frac{8 π}{15}$

answer is C.

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Detailed Solution

$x^{15} = - 1 \Rightarrow x = {(- 1)}^{\frac{1}{15}}$

$x = {(c i s π)}^{\frac{1}{15}}$

$x = c i s \frac{(2 k + 1) π}{15}, k = 0, 1, 2, 3, ...14$

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