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Q.

One ticket is drawn at random from a bag containing tickets numbered 1 to 40. The probability that the selected ticket has a number which is a multiple of 5 is

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a

\frac{1}{5}

b

\frac{1}{6}

c

\frac{5}{6}

d

\frac{1}{7}

answer is A.

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Detailed Solution

Given that, one ticket is drawn at random from a bag containing tickets numbered 1 to 40.
Let us assume that P(A) is the probability of an event “A”, n(S) is the total number of events in the sample space and n(A) is the number of favorable outcomes.
So,

n S = 40

.
The multiples of 5 from 1 to 40 are 5, 10, 15, 20, 25, 30, 35, and 40. So, the number of favorable outcomes n(A) is 8 and the total number of outcomes is 40.

P A = N u m b e r o f f a v o u r a b l e o u t c o m e s T o t a l n u m b e r o f o u t c o m e s .

P A = 840 P A = 15

Therefore, option 1 is correct.

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