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Q.

One ticket is selected at random from 50 tickets numbered 00, 01, 02 ...49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals

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a

$\frac{5}{14}$

b

$\frac{1}{14}$

c

$\frac{1}{4}$

d

$\frac{1}{50}$

answer is D.

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Detailed Solution

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$A = Events that sum of the digits on selected ticket is 8$

$B = Event that product of digits is zero$

$B = {00, 01, 02, 03, 04, 05, 06, 07, 08, 09, 10, 20, 30, 40}$

$A \cap B = \{08\} \Rightarrow n (A \cap B) = 1$

$P (\frac{A}{B}) = \frac{n (A \cap B)}{n (B)} = \frac{1}{14}$

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One ticket is selected at random from 50 tickets numbered 00, 01, 02 ...49. Then the probability that the sum of the digits on the selected ticket is 8, given that the product of these digits is zero, equals