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One unit of electricity is consumed by

$A, P = 40 W$ a bulb used for $t = 25$ hours
$B, P = 20 W$ bulb used for $t = 50$ hours
Both $A$ and $B$ are true as, energy $E$ in $kWh$ is best-related as

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E = Pt

E = \frac{Pt}{1000}

E = \frac{P}{1000}

E = \frac{t}{1000}

answer is B.

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Detailed Solution

Energy

E

kWh

is best-related as

E = \frac{Pt}{1000}

Energy in

kWh

is calculated as

E = P \times t

Where

P

is in

kW

and

t

is in hours
If P is in Watts, the relation would be changed to

E = \frac{Pt}{1000}

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