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One year ago, a man was 8 times as old as his son. Now his age is equal to the square of his son’s age. Find their present ages.

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49,7

48,7

7,7

8,7

answer is A.

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Detailed Solution

Concept- As given in the question we need to find the value of the man and his son's present age . to do so we can assume a variable and then by solving then we will get their present age.
Let’s take the present age of the man

And the present age of his son

So we can make equation ,
Hence, it is given that one year back the man

of his son's age .
Age one year back will be

and

, now the equation will form;

And now we have that the man age

(son age) 2

2………………………(2)
Let’s put equation 2 in 1, we will get 2
Question Image

Now we the two values of

. Now we will find which value is correct,

As it’s common that sons will be born after man and their ages cannot be same hence this value is incorrect.

Now we can say that this answer is correct .
The age of man =

Age of son

Hence, the correct option is 1.

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