OPQR is a square and M, N are the middle points of the sides PQ and QR, respectively, Then the ratio of the area of the square to that of triangle OMN is α:β then α+β=


detailed solution

Correct answer is 11

Let the coordinates of vertices O, P, Q, R be (0, 0), (a, 0), (a, a), (0, a), respectively. Then, we get the coordinates of M as (a, a/2) and those of N as (a/2, a). Therefore, the area of ΔOMN is 3a28 Area of squareArea of triangle=a23a28=83 Now α+β=11

Talk to our academic expert!


Please indicate your interest

Are you a Sri Chaitanya student?

Practice More Questions

Easy Questions

Moderate Questions

Difficult Questions

Download the app
brand logo

6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.


Sri Chaitanya College Admission Enquiries 040-66060606

Sri Chaitanya School Admission Enquiries 040-71045045 & 040-44600600 Ext 401, 402 & 425

facebook logoyoutube logotwitter logolinkedin logoinstagram logo

Quick Links


Study Material

Our Results





InfinityLearn App

playstore app

Copyright © 2023. All Rights Reserved 2023