Orange light of wavelength 6000×10−10m illuminates a single slit of width 0.6×10−4m. The maximum possible number of diffraction minima produced on both sides of the central maximum on screen is __________.

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Orange light of wavelength $6000 \times 10^{- 10}$ m illuminates a single slit of width $0.6 \times 10^{- 4} m$ . The maximum possible number of diffraction minima produced on both sides of the central maximum on screen is __________.

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Detailed Solution

For obtaining secondary minima at a point path difference should be integral of wavelength
$∴ d \sin θ = n λ \Rightarrow \sin θ = \frac{n λ}{d}$
For n to be maximum $\sin θ = 1$
$n = \frac{d}{λ} = \frac{6 \times 10^{- 5}}{6 \times 10^{- 7}} = 100$