Orange light of wavelength $6000\times {10}^{-10}m$  illuminates a single slit of width $0.6\times {10}^{-4}m$ . The maximum possible number of diffraction minima produced on both sides of the central maximum is __________

For obtaining secondary minima at a point path difference should be integral multiple of wavelength
 $\therefore d\sin \theta =n\lambda \Rightarrow \sin \theta =\frac{n\lambda }{d}$
For n to be maximum  $\sin \theta =1$
 $n=\frac{d}{\lambda }=\frac{6\times {10}^{-5}}{6\times {10}^{-7}}=100$
Total number of minima on one side=99 
Total number of minima=198.