Orange light of wavelength 6000×10−10 m illuminates a single slit of width 0.6×10−4m. The maximum possible number of diffraction minima produced on both sides of the central maximum is

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Orange light of wavelength $6000 \times 10^{- 10}$ m illuminates a single slit of width $0.6 \times 10^{- 4} m$ . The maximum possible number of diffraction minima produced on both sides of the central maximum is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 198.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{array}{l} For minima dsin θ = n λ \\ \Rightarrow \sin θ = \frac{n λ}{d} < 1 \\ \Rightarrow n < \frac{d}{λ} = \frac{0.6 \times 10^{- 4}}{6000 \times 10^{- 10}} = 100 \\ T h e 100^{t h} m i n i m a c o r r e s p o n d s t o i n f i n i t y . \\ S o, o n t h e s c r e e n 99 m i n i m a o n o n e s i d e i s o b t a i n e d \\ a n d 198 o n b o t h s i d e s . \end{array}$