Order of magnitude of density of uranium nucleus is $\left({\mathrm{m}}_{\mathrm{p}}=1.67\times {10}^{-27}\mathrm{kg}\right)$

Density is independent on atomic mass number.

$\text{ Nuclear density of an atom of mass number }A\text{, is }$

$D=\frac{\text{ mass }}{\text{ volume }}=\frac{A\left(1.67\times {10}^{-27}\right)}{\frac{4}{3}\pi {\left[1.25\times {10}^{-15}{A}^{1/3}\right]}^3}$

$\left[\therefore V=\frac{4}{3}\pi R^3,R=R_0{A}^{1/3},R_0=1.25\times {10}^{-15}\right]$

$\therefore D=2\times {10}^{17}{\mathrm{kgm}}^{-3}\text{. }$