Order of number of planes present in molecule which contains maximum number of atoms of corresponding molecule :

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${SF}_{6} > {IF}_{7} > {CH}_{4}$

$\begin{aligned} {CH}_{4} > {SF}_{6} > {IF}_{7} \end{aligned}$

${CH}_{4} > {IF}_{7} > {SF}_{6}$

$\begin{aligned} {IF}_{7} > {SF}_{6} > {CH}_{4} \end{aligned}$

answer is B.

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Detailed Solution

Each methane molecule contains 5 atoms total: 1 carbon atom, 4 hydrogen atoms, and 1 oxygen atom.

The octahedral form of ${SF}_{6}$ will have five atoms in the horizontal plane (4F-atoms and 1S atom)

${IF}_{7}$ contains seven Fluorine atoms and one Iodine atom.'

No. of such planes in $\begin{aligned} {CH}_{4} = 10 \end{aligned}$

No. of such planes in $\begin{array}{r} {SF}_{6} = 3 \end{array}$

No. of such planes in $\begin{array}{r} {IF}_{7} = 1 \end{array}$

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