Orientation of all electron pairs around the central atom in ${\mathrm{BrF}}_5$ molecule and shape of ${\mathrm{BrF}}_5$ molecule respectively is

${\mathrm{BrF}}_5({\mathrm{AB}}_5\mathrm{E} \mathrm{type}) \mathrm{contains} : 1 \mathrm{lone}-\mathrm{pair} \mathrm{and} 5 \mathrm{bond}-\mathrm{pairs}.$ 

Due to the presence of a lone pair  the shape changes from Octahedral to square pyramidal.