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Q.

Osmotic pressure of 30% solution of glucose is 1.20 atm and that of 3.42% solution of cane sugar is 2.5 atm. The osmotic pressure of the mixture containing equal volumes of the two solutions will be:

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a

2.5 atm

b

3.7 atm

c

1.85 atm

d

1.3 atm

answer is C.

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Detailed Solution

$\begin{array}{l} M (2 V) = M_{1} V + M_{2} V \\ M = \frac{M_{1} + M_{2}}{2} \\ M_{1} = \frac{1.2}{ST} \\ M_{2} = \frac{2.5}{ST} \end{array}$

$\begin{array}{l} M = \frac{3.7}{2 ST} \\ M = \frac{1.85}{ST} \\ \Rightarrow M \times S \times T = 1.85 atm \end{array}$

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Osmotic pressure of 30% solution of glucose is 1.20 atm and that of 3.42% solution of cane sugar is 2.5 atm. The osmotic pressure of the mixture containing equal volumes of the two solutions will be: