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Osmotic pressure of 500 ml solution containing 18 grams of non-volatile solute is 4.926 atm at 300 K. Molar mass of solute is

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120 g/mole

60 g/mole

200 g/mole

180 g/mole

answer is A.

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Detailed Solution

$π = C R T$
$\begin{array}{l} 4.926 = \frac{18}{M} \times \frac{1000}{500} \times 0.0821 \times 300 \\ M = 180 \end{array}$

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