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Osmotic pressure of a urea solution at $10^{o} C$ is 500 mm. Osmotic pressure of the solution become 105.3 mm. When itis diluted and temperature raised to $25^{o} C$ . The extent of dilution is

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4 times

7 times

5 times

6 times

answer is B.

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Detailed Solution

$\begin{array}{l} πV = nRT \\ \frac{500 V_{1}}{105 .3 V_{2}} = \frac{nR \times 283}{nR \times 298}; \Rightarrow \frac{V_{1}}{V_{2}} = \frac{1}{5} so V_{2} = 5 V_{1} \end{array}$

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