Out of the following salts identify the one which has maximum solubility (in M) :(P) Barium sulphate having Ksp=1.1×10−10(Q)) Aluminium phosphate having Ksp=6.3×10−19(R) Cadmium iodate having Ksp=3.2×10−8(S) Cuprous chloride having Ksp=1.2×10−6

In, BaSO4S2=1.1×10−10S=1.1×10−10 ⇒10−5(Q) In AlPO4S=6.3×10−19 ⇒10−10(R) In CdIO32 53.2×10−8 ⇒10−4(S) In CuClS=1.2×106 ⇒10−3

Out of the following salts identify the one which has maximum solubility (in M) :(P) Barium sulphate having Ksp=1.1×10−10(Q)) Aluminium phosphate having Ksp=6.3×10−19(R) Cadmium iodate having Ksp=3.2×10−8(S) Cuprous chloride having Ksp=1.2×10−6

In, BaSO4S2=1.1×10−10S=1.1×10−10 ⇒10−5(Q) In AlPO4S=6.3×10−19 ⇒10−10(R) In CdIO32 53.2×10−8 ⇒10−4(S) In CuClS=1.2×106 ⇒10−3

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Out of the following salts identify the one which has maximum solubility (in M) :
(P) Barium sulphate having $K_{sp} = 1 .1 \times 10^{- 10}$
(Q)) Aluminium phosphate having $K_{sp} = 6 .3 \times 10^{- 19}$
(R) Cadmium iodate having $K_{sp} = 3 .2 \times 10^{- 8}$
(S) Cuprous chloride having $K_{sp} = 1 .2 \times 10^{- 6}$

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Aluminium phosphate

Cuprous chloride

Cadmium iodate

answer is D.

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Detailed Solution

In, ${BaSO}_{4}$

$\begin{array}{l} S^{2} = 1.1 \times 10^{- 10} \\ S = \sqrt{1.1 \times 10^{- 10}} \Rightarrow 10^{- 5} \end{array}$

(Q) In ${AlPO}_{4}$

$S = \sqrt{6.3 \times 10^{- 19}} \Rightarrow 10^{- 10}$

(R) In $Cd {({IO}_{3})}_{2}$

$5 \sqrt{3.2 \times 10^{- 8}} \Rightarrow 10^{- 4}$

(S) In $CuCl$

$S = \sqrt{1.2 \times 10^{6}} \Rightarrow 10^{- 3}$

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Out of the following salts identify the one which has maximum solubility (in M) :(P) Barium sulphate having Ksp=1.1×10−10(Q)) Aluminium phosphate having Ksp=6.3×10−19(R) Cadmium iodate having Ksp=3.2×10−8(S) Cuprous chloride having Ksp=1.2×10−6

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