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Q.

Output of step down transformer provide 100 unit of electricity to some building per hour at 220 voltage. Ratio of turns is primary and secondary winding to transformer is 20 : 1 and overall efficiency $(η %)$ of transformer is 90%. Find average input current for transformer (1 unit of electricity = 1kWh and $η % = \frac{P o w e r_{o u t}}{P o w e r_{i n}} \times 100$ )

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a

40A

b

14A

c

25.25A

d

28A

answer is D.

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Detailed Solution

Energy transferred to house per hour = 100 KW
$\Rightarrow P_{o u t p u t} = 100 K W \Rightarrow P_{i n p u t} = \frac{P_{o u t p u t}}{n} = \frac{100 K W}{0.9} = \frac{1000 K W}{9} \frac{V_{i n}}{V_{o u t}} = \frac{20}{1} \Rightarrow V_{i n p u t} = 20 \times V_{o u t p u t} = 20 \times 220 = 4400 V \Rightarrow V_{i n p u t} I_{i n p u t} = P_{i n p u t} 4400 \times I_{i n p u t} = \frac{1000 \times 10^{3}}{9} I_{i n p u t} = 25.25 A$

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Output of step down transformer provide 100 unit of electricity to some building per hour at 220 voltage. Ratio of turns is primary and secondary winding to transformer is 20 : 1 and overall efficiency (η%) of transformer is 90%. Find average input current for transformer (1 unit of electricity = 1kWh and η%=PoweroutPowerin×100 )