Oxidation number of iodine in IO₃⁻ , IO₄⁻, KI and I₂ respectively are:

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+5, +7, -1, 0

-1, -5, -1, 0

-1, -1, 0, + 1

+3, +5, +7, 0

answer is C.

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Detailed Solution

${IO}_{3}^{-} : x + 3 (- 2) = - 1 \Rightarrow x = + 5 {IO}_{4}^{-} : x + 4 (- 2) = - 1 \Rightarrow x = + 7 KI : x + (- 1) = 0 \Rightarrow x = + 1 I_{2} : x = 0$

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