Oxidation number of $Cl$ in $CaOCl 2$ (Bleaching power) is:

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Zero, since it contains

Cl 2

+1 and -1 since it contains

ClO −

and

Cl −

+1, since it contains

ClO −

-1, since it contains

Cl

answer is D.

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Detailed Solution

$CaOCl 2$ can also be written as $Ca (OCl) Cl$ Hence oxidation no.of another $Cl$ in $OCl −$ is $- 2 + x = - 1, x = 2 - 1 = + 1$
Oxidation no.of another $Cl$ is -1 as it is present as $Cl −$ .

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