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Oxidation numbers of oxygen in $F_{2} O_{2}$ and $H_{2} O_{2}$ are respectively

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$+ 2$ and $- 1$

$- 2$ and $+ 2$

$- 2$ and $- 2$

$+ 2$ and $- 2$

answer is A.

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Detailed Solution

$F_{2} O$

$2 (- 1) + x = 0$

$\Rightarrow x = + 2$

$H_{2} O_{2}$

$2 (1) + 2 x = 0 \Rightarrow x = - 1$

So, the oxidation numbers of oxygen in $F_{2} O$ and $H_{2} O_{2}$ are $+ 2$ and $- 1$ .

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