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Oxidation numbers of $P$ in ${PO}_{4}^{3 -} .$ of $S$ in ${SO}_{4}^{2 -}$ and that of $Cr$ in ${Cr}_{2} O_{7}^{2 -}$ are respectively.

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$+5. + 6$ and $+ 6$

$+ 3, + 6$ and $+ 5$

$+ 5, + 3$ and $+ 6$

$- 3, + 6$ and $+ 6$

answer is A.

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Detailed Solution

$\begin{array}{l} {PO}_{4}^{3 -} (P = + 5) \\ {SO}_{4}^{2 -} (S = + 6) \\ {Cr}_{2} O_{7}^{2 -} (Cr = + 6) . \end{array}$

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