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Q.

Oxidation of 2 – Butene with Acidifide ${KMnO}_{4} / Δ$ gives

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a

2 moles of ${CH}_{3} COOH$

b

${CH}_{3} COOH + {CH}_{3} CHO$

c

2 moles of ${CH}_{3} CHO$

d

${CH}_{3} COOH + {CO}_{2}$

answer is A.

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Detailed Solution

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${CH}_{3} - CH = CH - {CH}_{3} + (O) \frac{{KMnO}_{4} / H^{+}}{Δ} 2 {CH}_{3} COOH$

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