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Q.

Oxidation of succinate ion produces ethylene and carbon dioxide. On passing 965 A current for 30 sec through an aqueous solution of potassium succinate, the total volume of gases liberated (at both cathode and anode) at NTP(22.4 lit) is:

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a

13.44 L

b

6.72 L

c

10.08 L

d

3.36 L

answer is D.

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Detailed Solution

Question Image

$2 H^{+} + 2 e^{-} \overset{}{\to} H_{2}$

2F – 4 mol gases

$Q = \frac{965 \times 30}{96500} = \frac{3}{10} = 0.3 F$

$0.3 F \overset{}{\to} \frac{4 \times 0.3}{2} = 0.6 m o l$

$0.6 \times 22.4 = 13.44 L$

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Oxidation of succinate ion produces ethylene and carbon dioxide. On passing 965 A current for 30 sec through an aqueous solution of potassium succinate, the total volume of gases liberated (at both cathode and anode) at NTP(22.4 lit) is: