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Q.

Oxidation of succinate ion produces ethylene and carbon dioxide. On passing 965 A current for 30 sec through an aqueous solution of potassium succinate, the total volume of gases liberated (at both cathode and anode) at NTP(22.4 lit) is:

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a

13.44 L

b

6.72 L  

c

10.08 L

d

3.36 L 

answer is D.

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Detailed Solution

Question Image

 

 

 

 

 

2H++2e−→ H2

2F – 4 mol gases

Q=965×3096500=310=0.3F

0.3F→ 4× 0.32=0.6 mol

0.6×22.4=13.44 L

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