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Oxidation potential of hydrogen electrode in contact with 0.05M $H_{2} S O_{4}$ solution is

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+ 0.59 V

+ 0.059 V

- 0.159 V

+ 0.0767 V

answer is A.

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Detailed Solution

N = M × Basicity = 0.05 × 2 = 0.1 N

E = $- \frac{0.059}{2} \log (\frac{1}{{(0.1)}^{2}})$

SRP of hydrogen electrode = -0.059

SOP = + 0.059

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