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Q.

Oxidation state of oxygen in compounds OF2 and Na2O respectively are

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a

-2, -1

b

-2, +2

c

+1, -l

d

+2, -2

answer is A.

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Detailed Solution

OF2, here EN of fluorine is more than oxygen,
So, oxidation state of fluorine = - |
and oxidation state of oxygen = + 2
In Na2O, oxygen has more electronegative value than sodium,
So, oxidation state of oxygen = - 2
and oxidation state of Na= +1

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