Q.

   Oxidation states of lead in  Pb3O4  are

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a

 +4, +3, +1 

b

+4, +2, +2 

c

+6, 0, +2 

d

+6, +1, +1 

answer is B.

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Detailed Solution

Pb3O4Pb+2O-2 + Pb2O3 In PbO, oxidation number of Pb=+2 In Pb2O3,      Pb=x     O=-2 2x + 3-2=0       x=+3 Oxidation number of Pb in Pb3O4=+2 and +3

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