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$Oxidation states of lead in$ ${Pb}_{3} O_{4}$ $are$

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+4, +3, +1

+4, +2, +2

+6, 0, +2

+6, +1, +1

answer is B.

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Detailed Solution

${Pb}_{3} O_{4} \to \overset{+ 2}{Pb} \overset{- 2}{O} + {Pb}_{2} O_{3} In PbO, oxidation number of Pb = + 2 In {Pb}_{2} O_{3}, Pb = x O = - 2 \Rightarrow 2 x + 3 (- 2) = 0 x = + 3 Oxidation number of Pb in {Pb}_{3} O_{4} = + 2 and + 3$

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