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Q.

Oxygen cannot exhibit higher oxidation states due to

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a

small size

b

more electronegativity

c

less density

d

absence of ‘d’ orbitals

answer is D.

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Detailed Solution

The electronic configuration of oxygen is 1s2,2s2,2p4, so we can see 4 electrons in s and 4 in p-orbital. Moreover they are no vacant d-orbitals.

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