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Q.

P and Q are two distinct points on the parabola, y2=4x, with parameters t and t1 respectively. If the normal at P passes through Q, then the minimum value of t12 is :

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a

2

b

8

c

6

d

4

answer is A.

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Detailed Solution

We know that normal at t1meets the parabola at t2

then t2=-t1-2t1

By applying this formula we get

t1=-t-2t      t2+t1t+2=0      0  t128  So,minimum value  of  t12=8

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P and Q are two distinct points on the parabola, y2=4x, with parameters t and t1 respectively. If the normal at P passes through Q, then the minimum value of t12 is :