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Q.

P and Q are two variable points on the axes of  x  and  y  respectively such that  |OP|+|OQ|=a,  then the locus of foot of perpendicular from origin on PQ is

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a

(xy)(x2+y2)=axy

b

(x+y)(x2+y2)=axy

c

(x+y)(x2+y2)=a(xy)

d

(x+y)(x2y2)=axy

answer is B.

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Detailed Solution

Question Image

 

 

 

 

 

 

 

 

Slope of OA is  y1x1
Sloper of  PQ=x1y1
EQ.of PQ is  xx1+yy1=x12+y12
OP+OQ=a
 x12+y12x1+x12+y12y1=a
 (x+y)(x2+y2)=axy

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