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Q.

P is a point (a, b) in the first quadrant. If the two circles which pass through P and touch both the coordinate axes cut at right angles, then

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a

a2 - 6ab + b 2= 0

b

a2 - 8ab + b2 = 0

c

a2 - 4ab + b2 = 0

d

a2 + 2ab - b2 = 0

answer is C.

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Detailed Solution

P(a, b) and eq of 1st circle is
x2+y22r1x2r1y+r12=0(1)
Eq of (2nd) circle is
x2+y22r2x2r2y+r22=0(2)
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(1) & (2) interest orthogonally, 4r1r2=r12+r22
and common chord (1) & (2) passes through (a, b) is
2(a+b)=r1+r2 and r1r2=a2+b2a24ab+b2=0

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