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$P \to Q$ is a zero order reaction. If the concentration of P decreases from 0.1M to 0.05M in 10 seconds, the concentration of P after 15 seconds time is

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0.05 M

0.025 M

0.02 M

0.01 M

answer is B.

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Detailed Solution

$t_{\frac{1}{2}} = \frac{{[A]}_{\circ}}{2 K}$

$10 = \frac{0.1}{2 K}$

$K = 5 \times 10^{- 3} L^{- 1} \sec^{- 1}$

$K = \frac{{[A]}_{\circ} - [A]}{t}$

$5 \times 10^{- 3} = \frac{0.1 - [A]}{15}$

$[A] = 0.025 M$

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