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P –V plots for two gases during adiabatic processes are shown in the figure. Plots 1 and 2 should correspond respectively to

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H_{2} a n d O_{2}

O2 and He

He and Ar

O_{2} a n d N_{2}

answer is B.

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Detailed Solution

Slope of Adiabatic curve $\frac{Δ P}{Δ V} = - γ \frac{P}{V}$

$γ_{m o n o} = \frac{5}{3}; γ_{d i a} = \frac{7}{5}$

$\Rightarrow γ_{m o n o} > γ_{d i a}$

so, slope will be steeper for monoatomic than diatomic gases.

hence, Slope – 1 for O₂, slope-2 for He.

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