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Q.

P1:y2=49x  and P2:x2=4ay are two parabolas. 

Equation of a tangent to the parabola P1 at a point where it intersects the parabola P2 is: 

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a

y=0

b

x2y+4a=0

c

xy=0

d

2xy4a=0

answer is C.

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Detailed Solution

Two parabolas intersect at the points  (0, 0)  and (4a, 4a).

Equation of the tangent to P1 at (0, 0) is x = 0 and at (4a, 4a) is 

y(4a)=2a(x+4a)

 x2y+4a=0

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