Paramagnetic nature of oxygen molecule is explained on the basis of its electronic configuration of

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${(π 2 p_{X})}^{1}, {(π 2 p_{y})}^{1}$

${(π^{*} 2 p_{x})}^{1}, {(π^{*} 2 p_{y})}^{1}$

${(σ^{*} 2 s)}^{1}, {(π 2 p_{y})}^{1}$

$(σ 2 s)^{1}, {(π^{*} 2 p_{y})}^{1}$

answer is B.

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Detailed Solution

According to molecular orbital electronic configuration of $O_{2}$ _,two unpaired electrons in antibonding molecular orbitals leads to its paramagnetic nature

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