Particles of masses 200 gram and 100 gram have position vectors 1i^ + 2j^ + 10k^ and -1i^ + 2j^ + 3k^. Position vector of their centre of mass is

r→CM = m1r→1 + m2 r→2m1 + m2 = i^ + 6j^ + 23k^ 3

Particles of masses 200 gram and 100 gram have position vectors 1i^ + 2j^ + 10k^ and -1i^ + 2j^ + 3k^. Position vector of their centre of mass is

r→CM = m1r→1 + m2 r→2m1 + m2 = i^ + 6j^ + 23k^ 3

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Particles of masses 200 gram and 100 gram have position vectors $(1 \hat{i} + 2 \hat{j} + 10 \hat{k}) and (- 1 \hat{i} + 2 \hat{j} + 3 \hat{k})$ .
Position vector of their centre of mass is

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$\frac{\hat{i} + 6 \hat{j} - 23 \hat{k}}{3}$

$\frac{\hat{i} - 6 \hat{j} + 23 \hat{k}}{3}$

$\frac{\hat{i} + 6 \hat{j} + 23 \hat{k}}{3}$

$\frac{\hat{i} - 6 \hat{j} - 23 \hat{k}}{3}$

answer is C.

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${\vec{r}}_{CM} = \frac{m_{1} {\vec{r}}_{1} + m_{2} {\vec{r}}_{2}}{m_{1} + m_{2}} = \frac{\hat{i} + 6 \hat{j} + 23 \hat{k}}{3}$

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Particles of masses 200 gram and 100 gram have position vectors 1i^ + 2j^ + 10k^ and -1i^ + 2j^ + 3k^. Position vector of their centre of mass is

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Particles of masses 200 gram and 100 gram have position vectors $(1 \hat{i} + 2 \hat{j} + 10 \hat{k}) and (- 1 \hat{i} + 2 \hat{j} + 3 \hat{k})$ .
Position vector of their centre of mass is