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Particles of masses m₁ and m₂ are at a fixed distance apart. If the gravitational field strength at m₁ and m₂ are ${\vec{I}}_{1} and {\vec{I}}_{2}$ respectively. Then,

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$m_{1} \vec{I_{2}} + m_{2} \vec{I_{1}} = 0$

$m_{1} \vec{I_{2}} - m_{2} \vec{I_{1}} = 0$

$m_{1} \vec{I_{1}} - m_{2} \vec{I_{2}} = 0$

$m_{1} \vec{I_{1}} + m_{2} \vec{I_{2}} = 0$

answer is A.

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Detailed Solution

${\vec{I}}_{1} = \frac{{Gm}_{2}}{d^{2}} and {\vec{I}}_{2} = - \frac{{Gm}_{1}}{d^{2}}$

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