Passage :

In carbon atom one of the 2s electron goes to the 2p level. Then 2s and $2{\text{p}}_x,{\text{ 2p}}_{\text{y}},{\text{ 2p}}_{\text{z}}$ orbital’s of ‘C’ atom undergoes ${\text{sp}}^{\text{3}}$  hybridization and produce four ${\text{sp}}^{\text{3}}$ hybrid orbitals. These four ${\text{sp}}^{\text{3}}$ hybrid orbital’s have One electron each.

The electronic configuration of ${\text{H : 1s}}^1$  The 1s orbital of one ‘H’ atom and the one ${\text{sp}}^{\text{3}}$ hybrid orbital of ‘C’ atom overlap to form bond.

Q. Hybridization of ‘C’ in $C{H}_4$ molecule is