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${PbCl}_{4}$ exists, but ${PbBr}_{4}$ and ${PbI}_{4}$ do not. This is because of

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Bromide and iodide are bigger in size

More electropisitive character of ${Br}_{2}$ and $I_{2}$

Inability of bromine and iodine to oxidise ${Pb}^{2 +}$ to ${Pb}^{4 +}$

Chlorine is a gas, but bromine is a liquid and iodine is a solid.

answer is A.

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Detailed Solution

${Br}^{-} and I^{-}$ are powerful reducing agents which reduces ${Pb}^{4 +} \overset{}{\to} {Pb}^{2 +}$

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