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Q.

PbS+H2O2→PbSO4+H2O

In the balance equation of the above reaction, number of electrons transferred from each molecule of H2O2  to lead sulphide is

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a

4

b

2

c

8

d

1

answer is B.

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Detailed Solution

PbS+4H2O2→PbSO4+4H2O

From each H2O2  molecule, 2 electrons are transferred such that a total of 8 electrons to PbS. The change in the oxidation state of the sulphur is from – 2 to +6.

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PbS+H2O2→PbSO4+H2O In the balance equation of the above reaction, number of electrons transferred from each molecule of H2O2  to lead sulphide is