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${Pb}_{(s)} |{PbSO}_{4 (saturated)}| |{PbI}_{2 (saturated)}| {Pb}_{(s)}$ . Which of the following expressions represent the EMF of the above cell at 25⁰ C, (a = activity)

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$E = \frac{0 .0592}{2} \log \frac{[a_{{Pb}^{+ 2}}] RHS}{[a_{{Pb}^{2 +}}] LHS}$

$E = \frac{0 .0592}{2} \log \frac{[a_{{Pb}^{+ 2}}] LHS}{[a_{{Pb}^{2 +}}] RHS}$

$E = \frac{0 .0592}{2} \log \frac{K_{sp ({pbI}_{2})}}{K_{sp [{PbSO}_{4}]}}$

answer is A.

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Detailed Solution

$E = \frac{0 .591}{2} \log \frac{[{Pb}^{+ 2}] RHS}{[{Pb}^{+ 2}] LHS}$

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