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Q.

(P) Cis-2-butenetrans-2-butene,ΔH1

(Q) Cis-2-butene1-butene,ΔH2

(R) Trans-2-butene is more stable than cis-2-butene

(S)  Enthalpy of combustion of  1 -butene,

ΔH=-649.8 kcal/mol

(T) 9ΔH1+5ΔH2=0

(U) Enthalpy of combustion of trans-2-butene, ΔH=-647.0 kcal/mol

The value of  ΔH1 and ΔH2 in kcal/ mole are :

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a

-2,3.6

b

 1.8,-1.0

c

-5,9

d

-1.0,1.8

answer is A.

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Detailed Solution

 Cis-2-butene A

 trans-2-butene B

 1-Butene C

ΔH1=ΔHC(A)ΔHC(B)

ΔH2=ΔHC(A)ΔHC(C)

ΔH1ΔH2=ΔHC(C)ΔHC(B)

=649.8+647.0=2.8

Also, 9ΔH1+5ΔH2=0

14ΔH1=2.8×5

ΔH1=1.0

and ΔH2=+95=+1.8

Hence, option A is correct.

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