Q.

PCl5 dissociates as PCl5(g)PCl3(g)+Cl2(g)

5 moles of PCl5 are placed in a 200 litre vessel which contains 2 moles of N2 and is maintained at 600 K. The equilibrium pressure is 2.46 atm. The equilibrium constant Kp for the dissociation of PCl5 is____________ ×10-3. (nearest integer)
(Given:R=0.082 L atm K-1 mol-1 : Assume ideal gas behaviour)

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answer is 1107.

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Detailed Solution

Given : 2 mole of N2 gas was present as inert gas. Equilibrium pressure = 2.46 atm

PCl5(g)PCl3(g)+Cℓ2(g) t=0500t=Eqm5xxx

from ideal gas equation

 2.46×200=(5x+x+x+2)×0.082×600 x=3 KP=nPCl3×nCl2nPCl5×[Ptotalntotal] 3×32×2.4610=1.107=1107×103

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